6k^2-140=11k

Solution for 6k^2-140=11k equation:

6k^2-140=11k

We move all terms to the left:

6k^2-140-(11k)=0

a = 6; b = -11; c = -140;
Δ = b2-4ac
Δ = -112-4·6·(-140)
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3481}=59$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-59}{2*6}=\frac{-48}{12}
=-4
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+59}{2*6}=\frac{70}{12}
=5+5/6
$